Joylin must stack 3 blocks identical to the one shown below.
What strategy for stacking the blocks will produce a stack with the least surface area?
1)Create a stack where the 5-inch-by-6-inch faces of the blocks touch
2)Create a stack where the 5-inch-by-8-inch faces of the locks touch.
3)Create a stack where the 6-inch-by-8-inch faces of the blocks touch.
4)Create a stack where two different sized faces of the blocks touch.

c, Create a stack where the 6-inch-by-8-inch faces of the blocks touch.

i did the test

Step-by-step explanation:

A

Step-by-step explanation:

Solution:-

- The block has the following dimensions:

                     ( L x w x h ) = ( 8 x 5 x 6 ) in

- We will determine the surface area of each unique face of the block given in the attachment.

- Surface area of the face ( 8 x 5 ):

                 Area = ( 8 )*( 5 )

                 Area = 40 in^2

- Surface area of the face ( 8 x 6 ):

                 Area = ( 8 )*( 6 )

                 Area = 48 in^2

- Surface area of the face ( 6 x 5 ):

                 Area = ( 5 )*( 6 )

                 Area = 30 in^2

- see that a stack 3 identical boxes would have the lowest face-surface area where 5-inch-by-6 inch faces of the block touch. With the lowest area = 30 in^2.

the second one is d :)