Just no. 3 and 4, and also the QUESTIONS letters A and B Thank u so much for whom will help me!

Step-by-step explanation:

#3x² + 2x - 48 = 0

We can solve it differently, by completing a square:

x² + 2x + 1 - 49 = 0(x + 1)² - 49 = 0(x + 1)² = 49(x + 1)² = 7²√(x + 1)² = √7²x + 1 = ± 7x = - 1 ± 7x = -8, x = 6#43x² - 21x - 6 = 0

Divide all terms by 3 to simplify:

x² - 7x - 2 = 0

Find the discriminant:

D = (-7)² - 4*1*(-2) = 49 + 8 = 57

The roots are:

x = (-(-7) ± √57)/2 = (7 ± √57)/2, (leave as is since no more simplification)

Questions

a) For the #3 used the method of completing the square and for the #4 used quadratic formula.b) Completing the square and finding square roots. The quadratic formula.

The constants, -3 and -8, are like terms

The terms 3p and p are like terms

The terms in the expression are p^2, -3, 3p, -8, p, p^3

The expression contains 6 terms.

Like terms have the same variables raised to the same powers.