Kenji has at most $30 to spend on lily bulbs and tulip bulbs at his local flower store. lily bulbs cost $4 each, and tulip bulbs cost $2 each. tax is included in the prices of the bulbs.

Kenji has at most $30 to spend on lily bulbs and tulip bulbs at his local flower store. Lily bulbs cost $4 each, and tulip bulbs cost $2 each. Tax is included in the prices of the bulbs.

Create a constraint that can be used to represent all possible numbers of lily bulbs, x, and tulip bulbs, y, Kenji can buy

Let "x" be the number of lily bulbs and "y" be the number of tulip bulbs Kenji bought.

Given that Lily bulbs cost $ 4 each

Then cost of "x" lily bulbs =

Thus cost of "x" lily bulbs is $ 4x

Given that tulip bulbs cost $2 each

Then cost of "y" lily bulbs =

Thus cost of "y" lily bulbs is $ 2y

So the total of "x" lily bulbs and "y" tulip bulbs is represented as: $ (4x + 2y)

Kenji has at most $30 to spend on lily bulbs and tulip bulbs at his local flower store, so

Here we have used less than or equal to symbol to denote atmost 30

Create a constraint that can be used to represent all possible numbers of lily bulbs, x, and tulip bulbs, y, Kenji can buy:

It is the first choice.

Step-by-step explanation:

This is a sequence where

the next term is obtained by adding 6.

first term = -9 + 6(0) = -9

second term = -9 + 6(1) = -3

third term = -9 + 6(2) = 3

4th term = -9 + 6(3)  = 9  

and 81 = -9 + (6*15).

So the answer is  Sigma (-9 + 6n)  from n= 0 to n = 15.