Mathematics: Kent swam 150 m up a river that has a steady current in 5 minutes and returned downstream in 3 minutes. How fast would he have swum in still water, and what? is the speed of the current

Kent swam 150 m up a river that has a steady current

Ответ:

ubaldo7410

25.01.2022

The current of the stream is 1.2 meters per minute.

Explanation:

v = (150 / 5) - x

v = (150 / 3) + x

(150 / 5) - x = (150 / 3) + x

Now, solve for x:
(150 / 5) = (150 / 3) + 2x
(3 / 5) = 2x
x = 6 / 5 = 1.2

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Ответ:

cece4874

16.10.2020

Mathematics

We can solve these equations by using substitution method where you substitute one equation to the other and solve for the value of the other variable. We do as follows:

y = 2x^2
y = –3x −1

2x^2 = –3x −1
2x^2 +3x +1 = 0

x1= -0.5
x2 = -1
y1 = 0.5
y2 = 2

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Kent swam 150 m up a river that has a steady current in 5 minutes and returned downstream in 3 minutes. How fast would he have swum in still water, and what? is the speed of the current

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