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The half-life of c-14 is 5,730 years. the general equation for first-order radioactive decay is: ln(x0 / x) = kt, where x0 is the original amountfor the special case of half life: ln(2) = k(5730), so k = 1.21 x 10^-4for a skull w/51% of initial content remaining: ln(1/0.51) = (1.21 x 10^-4)tt = 5566 years