Last year a man earned 19,200. this year his salary

Ответ:

nmknightp02

11.03.2022

Last year a man earned 19,200. This year his salary increased to 20,736. What was the percent of his increase ?

Solution

Here we have to use the formula.

Percentage of increase = $\frac{Increase}{Original number} *100$

Increase in earning = 20, 736 - 19,200 = $1536

Original number = 19,200

Now plugin these values into the formula, we get

Percentage of increase = $\frac{1536}{19200} *100 = \frac{153600}{19200} = 8$ %

The answer is 8%

Hope you will understand the steps.

Thank you. :)

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fatty18

01.01.2021

we conclude that:

$\:9x^0y^{-3}=\frac{9}{y^3}$

Step-by-step explanation:

Given the expression

$9x^0y^{-3}$

Apply exponent rule: $a^{-b}=\frac{1}{a^b}$

$\:9x^0y^{-3}=9\cdot \:\frac{1}{y^3}x^0$

Apply rule: $a^0=1,\:a\ne \:0$

$=9\cdot \:1\cdot \frac{1}{y^3}$

Multiply fractions: $a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}$

$=1\cdot \frac{1\cdot \:9}{y^3}$

Refine

$=\frac{9}{y^3}$

Thus, we conclude that:

$\:9x^0y^{-3}=\frac{9}{y^3}$

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