Leanne is trying to convert x^2+4x-6=0 the standard form to vertex form by completing the square which equation shows the correct form

In vertex form we have y =      (x + 2)^2 - 10

Step-by-step explanation:

x^2+4x-6=0 is in standard form; we want it in the form y - k = a(x - h)^2.

Complete the square within  x^2+4x-6=0

We get  x^2 + 4x - 6 = 0  =>  x^2 + 4x + 4 - 4 - 6, or

                                          y =      (x + 2)^2 - 10

Comparing this to              y = (x - h)^2 - 10, we see that the vertex is at

                                            (h, k) :  (-2, -10)

Step-by-step explanation:

Let 0 = y to not mix up the numbers.

we are trying to get to this form:

Let's group the variables to make it easier for us to complete the square.

Complete the square by taking the number next to the x variable (4) divide it by 2 (4/2=2) and square it ()

Add this.

You also have to add it to the right side, but since we're looking to isolate y again, we're going to have to move it to the left side eventually; therefore, we can simply change the sign and add it to the left side.

In other words, instead of doing this:

I'm going to directly say the opposite of +4 is -4

Now factor the parentheses and combine like terms;

And like we said y = 0, so change that...