Let a = (0, 12) and b = (25, 12). if possible, find coordinates for a point p on the x-axis that makes angle apb a right angle.

Since any right triangle formed between points A, B, and a point on thee x-axis would have it's longest side, or hypotenuse, as AB, with a length of 25, there is more than one point P along the x-axis that could form a right angle APB. One of those points is (9,0). This would give side AP a length of 15, and side PB a length of 20, forming a right triangle, verified using the pythagorean theorum, 25^2 = 15^2 + 20^2 or 625 = 225 + 400.

x^2+(y-10)^2=64

Step-by-step explanation:

In standard form.

x^2+(y-10)^2=64