Mathematics: Let a={2, 4, 6, 8} and b={2, 3, 5, 7, 9} compute n(a)

Let a={2, 4, 6, 8} and b={2, 3, 5, 7, 9} compute n(a)

Ответ:

AnimePo2020

01.06.2020

Mathematics

Answer with explanation:

Given two sets

A={2, 4, 6, 8} and B={2, 3, 5, 7, 9}

⇒n(S)=Cardinality of a set

Means the number of distinct elements in a Set is called it's cardinal number.

→In Set A,total number of distinct elements is 4.

n(A)=4

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Ответ:

myronpacis1128

07.11.2021

Mathematics

Check the picture below.

$\bf \textit{area of this trapezoid}\\\\
A=\cfrac{{AB}({BC}+{AD})}{2}\\\\
-------------------------------\\\\
\textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 5}}\quad ,&{{ 0}})\quad 
% (c,d)
B&({{ 4}}\quad ,&{{ 3}})\\
B&({{ 4}}\quad ,&{{ 3}})\quad 
% (c,d)
C&({{ 10}}\quad ,&{{ 5}})\\
A&({{ 5}}\quad ,&{{ 0}})\quad 
% (c,d)
D&({{ 8}}\quad ,&{{ 1}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
$

$\bf AB=\sqrt{(4-5)^2+(3-0)^2}\implies AB=\sqrt{1+9}\implies AB=\sqrt{10}
\\\\\\
BC=\sqrt{(10-4)^2+(5-3)^2}\implies BC=\sqrt{36+4}\implies BC=\sqrt{40}
\\\\\\
AD=\sqrt{(8-5)^2+(1-0)^2}\implies AD=\sqrt{9+1}\implies AD=\sqrt{10}\\\\
-------------------------------$

$\bf \begin{cases}
\sqrt{40}\\
\qquad \sqrt{2^2\cdot 10}\\
\qquad 2\sqrt{10}
\end{cases}\qquad A=\cfrac{h(x+y)}{2}\implies A=\cfrac{\sqrt{10}(2\sqrt{10}+\sqrt{10})}{2}
\\\\\\
A=\cfrac{\sqrt{10}(3\sqrt{10})}{2}\implies A=\cfrac{3(\sqrt{10})^2}{2}\implies A=\cfrac{30}{2}\implies A=15$

Atrapezoid has vertices at a(5, 0)a(5, 0) , b(4, 3)b(4, 3) , c(10, 5)c(10, 5) , and d(8, 1)d(8, 1) ,

Atrapezoid has vertices at a(5, 0)a(5, 0) , b(4, 3)b(4, 3) , c(10, 5)c(10, 5) , and d(8, 1)d(8, 1) ,

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Let a={2, 4, 6, 8} and b={2, 3, 5, 7, 9} compute n(a)

Ответ:

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