Let b1 =
and b2 =
then answer the following:
a. find 1 ⋅ b1 + 0 ⋅ b2.
b. find 0 ⋅ b1 + 1 ⋅ b2.
c. find 1 ⋅ b1 + 1 ⋅ b2.
d. find 3 ⋅ b1 + 2 ⋅ b2.
e. find 0 ⋅ b1 + 0 ⋅ b2.
f. find x ⋅ b1 + y ⋅ b2 for x, y real numbers.
g. summarize your results from parts (a)–(f). can you use b1 and b2 to define any point in ℝ2?

If you wrote this in point-slope form, it’ll be y+8=-6(x-2).

This equation written in slope intercept form would be y = -6x+4.

He messed up because he was supposed to change the double negative into a positive then solve. He was not supposed to add 8 on both sides.

So, the answer is y = -6x+4.

Hope this helps!