Let be the function . Then the quotient can be simplified

Ответ:

lauraleemartinez

07.02.2022

Step-by-step explanation:

$\frac{f(7+h)-f(7)}{h}\\=\frac{\frac{1}{(7+h)+3}-\frac{1}{7+3}}{h}\\=\frac{\frac{1}{10+h}-\frac{1}{10}}{h}\\=\frac{\frac{10-(10+h)}{10(10+h)}}{h}\\=\frac{-h}{10(10+h)h}}\\=\frac{-1}{10h+100}} \text { for h} \neq 0$

so a=10, b=100

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Ответ:

ytcampos6

26.11.2020

Mathematics

I Feel you.

Step-by-step explanation:

I just said no problem to a question

I just got reported it said Your content has been removed for violating our Community Guidelines why

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Let be the function $\frac{1}{x+3}$ . Then the quotient $\frac{f(7+h)-f(7)}{h}$ can be simplified to $\frac{-1}{ah+b}$ for:

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Let be the function . Then the quotient can be simplified to for:

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Let be the function $\frac{1}{x+3}$ . Then the quotient $\frac{f(7+h)-f(7)}{h}$ can be simplified to $\frac{-1}{ah+b}$ for: