Let f (x) = -6x +4 and g(x) = 4x – 3 What is the rule for (f.g)(x)?
(fog)(x) = -2.2 - - 1
(f.g) (2) = –24x² – 2x – 12
(f.g) (2) = -24x2 - 12
(f.g)(x) = -24x2 + 3x - 12

x = -7/2

y = -13/2

Step-by-step explanation:

Solve for y in the first equation.

y = 4 + 3x

Put y as 4 + 3x in the second equation and solve for x.

-9x + 5(4 + 3x) = -1

-9x + 20 + 15x = -1

6x + 20 = -1

6x = -21

x = -21/6

x = -7/2

Put x as -7/2 in the first equation and solve for y.

y = 4 + 3x

y = 4 + 3(-7/2)

y = 4 + -21/2

y = -13/2