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matrixoz1262
19.07.2019 •
Mathematics
Let f(x)=x^2+10x+37 .what is the vertex form of f(x)? what is the minimum value of f(x)? enter your answers in the boxes.vertex form: f(x)= minimum value of f(x):
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Ответ:
Thank you for the explanation!
To all future users: Here is simply the answers so you aren't confused.
Vertex form: f(x) = (x+5)²+12
Minimum value of f(x): 12
I hope that clears up any confusion...
Good luck! :)
Ответ:
Standard form:
Vertex form:
Group the first two terms:
Now complete the square inside the parenthesis. Take half of the second term and square it, then add it and subtract it inside the parenthesis(so we don't change the function):
Half of 10 is 5, 5 squared is 25:
Factor the perfect square(
Simplify:
This is the function in vertex form.
The minimum value is the vertex, we can find this just by looking at our function in vertex form.
Vertex form:
'h' is -5 and 'k' is 12
So our minimum is:
Ответ:
D
Step-by-step explanation: