fortwill05
17.01.2021 •
Mathematics
let f(x) = x^3+3x^2-x-3. Find the polynomial function each of whose roots are two less than the roots of f(x)
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Ответ:
Step-by-step explanation:
f(x) = x³ + 3x² - x - 3 = x²(x + 3) - (x + 3)
= (x² - 1)(x + 3) = (x + 1)(x - 1)(x + 3).
The roots of f(x) are x = -3, -1 and 1.
=> The new roots are x = -5, -3 and -1.
=> g(x) = (x + 5)(x + 3)(x + 1) = x³ + 9x² + 23x + 15.
Ответ:
i wish you good luck.
also, is that madden 21?