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zacharysharpe2805
zacharysharpe2805
10.12.2020 • 
Mathematics

Let r = ⟨5, –1⟩, s = ⟨6, 0⟩, and t = ⟨–1, –3⟩. Aaron incorrectly determined 2r + 4s – 7t as ⟨41, –23⟩. Review his calculations. 2r + 4s – 7t
2⟨5, –1⟩ + 4⟨6, 0⟩ – 7⟨–1, –3⟩
⟨10, –2⟩ + ⟨24, 0⟩ + ⟨7, –21⟩
⟨41, –23⟩

What mistake did Aaron make?

He added ⟨10, –2⟩ + ⟨24, 0⟩ + ⟨7, –21⟩ incorrectly.
He should have subtracted ⟨7, –21⟩ rather than add.
He did not correctly distribute 4 to both components of s.
He did not correctly distribute the negative when subtracting 7t.

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