Mathematics: let s = 100/(t2+12) be the position function of a particle moving along a coordinate line, where s is in feet and t is in seconds. (a) find the maximum speed of the particle for t 0. if appropriate, leave your answer in radical form.

let s = 100/(t2+12) be the position function of

daonewest09

09.01.2022

$v(t_{0})=\frac{-200t_{0} }{(t_{0}^{2}+12)^{2}} ft/s$

Step-by-step explanation:

Let's remember we could write the speed as a function of position taking the derivative whit respect to time.

$v(t)=\frac{ds}{dt}= \frac{-200t}{(t^{2}+12)^{2}}$

Now, evaluating the speed at t₀, we have:

$v(t_{0})=\frac{-200t_{0}}{(t_{0}^{2}+12)^{2}} ft/s$

It would be the maximun speed at that time.

Have a nice day!

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lburch112

13.04.2022

x is 10 y is 5.8

Step-by-step explanation:

x=y+4.2=10

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