bneilesauger
04.12.2020 •
Mathematics
Let sin(2x)-sin(x)=0,where 0<x<2pi. what are the possible solutions for x?
a. {pi/6,5pi/6}
b. {pi/3, 5pi/3}
c. {pi/6,pi/2,5pi/6,3pi/2}
d. {0,pi/3,pi,5pi/3}
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Ответ:
The ratios are both identical (3/5 and 3/5).
Step-by-step explanation:
sin x° is equivalent to O/H, or the opposite/hypotenuse sides of the triangle. Therefore:
sin x° = 3/5.
cos y° is equivalent to A/H, or the adjacent/hypotenuse sides of the triangle.
cos y° = 3/5.
The ratios are identical.