Mathematics: Log base 6 (3x) + log base 6 (x-4) = 2

Log base 6 (3x) + log base 6 (x-4) = 2 - id636421892632, kellynadine02

Ответ:

aricketts3901

31.12.2021

$D:3x0 \wedge x-40\\
D:x0 \wedge x4\\
D:x4\\\\
\log_63x+\log_6(x-4)=2\\
\log_63x(x-4)=\log_636\\
3x(x-4)=36\\
3x^2-12x=36\\
3x^2-12x-36=0\\
x^2-4x-12=0\\
x^2+2x-6x-12=0\\
x(x+2)-6(x+2)=0\\
(x-6)(x+2)=0\\
x=6 \vee x=-2\\
-2\not \in D \Rightarrow x=6$

0,0(0 оценок)

Ответ:

lineaeriksen

25.09.2020

Mathematics

9s = 36
s = 4
7s = 28
7 sweets cost 28 pence

0,0(0 оценок)

Log base 6 (3x) + log base 6 (x-4) = 2

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question