Lynn rents a luxury car at the edmonton internacional airport. she wants a nice
vehicle for her 3 day trip. she figures she will put on about 400 km during the three
days.
a. what would be the cost of the standard daily rate plus mileage plan?
b. what would be the cost of the unlimited mileage plan?
c. which is the better plan?

Step-by-step explanation:

Looking at the table,

a) the standard daily rate for a luxury car is $70. Since Lynn wants to rent the luxury car for 3 days, it means that the standard rate for 3 days would be

3 × 70 = $210

She figures she will put on about 400 km during the three

days. The cost of renting the luxury car per kilometer(mileage) is 30 cents. Therefore, the cost for 400 kilometers would be

400 × 30 = 12000 cents.

Converting 12000 cents to dollars, it becomes

12000/100 = $120

Total cost of renting the luxury car would be

120 + 210 = $330

b) the daily cost of the unlimited mileage daily for the luxury car is $105

Total cost of renting the luxury car for 3 days would be

105 × 3 = $315

c) the standard daily rate is better because it is cheaper

-8

Step-by-step explanation:

General form of a quadratic is:

Ax² + Bx + C

Where B is the coefficient of x

For the given quadratic, B = -8