M1 and m42 have roadworks. 50/50 chance of getting delayed on m42 and 75% chance on m1. what are the chances of not been delayed

Let's use the following notation:

p1 - probability of getting delayed on M1
p2 - probability of getting delayed on M2
p3 - probability of getting delayed altogether

p1 = 50%
p2 = 75%

I will assume that probability of taking each road is the same. If it isn't, this answer is incorrect!

p3 = 50% * p1 + 50% * p2
p3 = 0.5 * p1 + 0.5 * p2
p3 = 0.5 * 50% + 0.5 * 75%
p3 = 0.5 * 0.5 + 0.5 * 0.75
p3 = 0.25 + 0.375
p3 = 0.625

p4 - probability of NOT being delayed
p4 = 1 - p3
p4 = 1 - 0.625 = 0.375 = 37.5%

Hope this helps

The word problem is described.

Each child will get of wheat.

Step-by-step explanation:

Word Problem:

A woman have 0.5 kg of wheat. She need to distribute it equally among her three children. How much amount of wheat will each child get?

Solution:

Total weight of wheat  =

Number of children = 3

Amount of wheat each child will get =

Thus, each child will get of wheat.