Match the following items. in a group of 100 persons, 85 had rh positive blood (rh factor present), 45 had type o blood, and 38 had both type o and rh positive blood. if one person had been selected at random from the group, what would the probability be: 1. that his blood type was type o and rh+? 1 19/50 2. that his blood type was not o? 4 7/100 3. that his blood type was rh-? 5 3/20 4. that his blood type was type o and rh-? 3 11/20 5. that his blood type was rh+? 2 17/20 6. that his blood type was not type o or else was rh+? 6 93/100

Part 1) that his blood type was Type O and Rh+?
we know that
38 out of 100 have type O and Rh+
so
 the probability is 38/100,
which simplifies to 38/100> divide by 2 both members> 19/50 

the answer part 1) is
19/50

part 2) that his blood type was not O?
we know that
45 out of 100 have type O
so
 55 out of 100 don't have type O,
and the probability is > 55/100> divide by 5 both members> 11/20 

the answer part 2) is
11/20

Part 3) that his blood type was Rh-?
we know that
85 out of 100 have Rh+
so
15 out of 100 have Rh-,
so
 the probability is 15/100> divide by 5 both members> 3/20 

the answer part 3) is
3/20

Part 4)that his blood type was Type O and Rh-?
we know that
45/100 or 9/20 have type O
and
15/100 or 3/20 have Rh-,
so
multiply the fractions to get > (9/20)*(3/20)> 27/400
 which is about 7/100 

the answer  Part 4) is
7/100

Part 5) that his blood type was Rh+?
we know that
85/100 or 17/20 for Rh+ 

the answer part 5) is
17/20

Part 6) that his blood type was not Type O or else was Rh+?
we know that
O and Rh+ is 38/100,
 non-O is 55/100,
and
add them to get 93/100

the answer part 6) is
93/100

Part 1) that his blood type was Type O and Rh+?

we know that

38 out of 100 have type O and Rh+

so

the probability is 38/100,

which simplifies to 38/100> divide by 2 both members> 19/50

the answer part 1) is

19/50

part 2) that his blood type was not O?

we know that

45 out of 100 have type O

so

55 out of 100 don't have type O,

and the probability is > 55/100> divide by 5 both members> 11/20

the answer part 2) is

11/20

Part 3) that his blood type was Rh-?

we know that

85 out of 100 have Rh+

so

15 out of 100 have Rh-,

so

the probability is 15/100> divide by 5 both members> 3/20

the answer part 3) is

3/20

Part 4)that his blood type was Type O and Rh-?

we know that

45/100 or 9/20 have type O

and

15/100 or 3/20 have Rh-,

so

multiply the fractions to get > (9/20)*(3/20)> 27/400

which is about 7/100

the answer  Part 4) is

7/100

Part 5) that his blood type was Rh+?

we know that

85/100 or 17/20 for Rh+

the answer part 5) is

17/20

Part 6) that his blood type was not Type O or else was Rh+?

we know that

O and Rh+ is 38/100,

non-O is 55/100,

and

add them to get 93/100

the answer part 6) is

93/100

Ihad to look for the options and here is the answer:
based on the given situation above, i can say that the sample that would give jared the most accurate test results is a sample consisting of every 20th lightbulb. this answer is based on the actual options of this question.