srichard9955

23.08.2019 •

Mathematics

Me asap!
(8x-2y)+(3x-4y)
a. 11x+8y
b. 4x-y
c. 11x-6y
d. 5x+2y

Solved

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Ответ:

DragonLovely

10.04.2023

Mathematics

Answer/Step-by-step explanation:

Recall: if two figures are similar, we know that the ratio of their areas = the square of the ratio of their corresponding sides

Apply this knowledge to solve the problems given.

✔️Problem 1 (4-sided polygon):

Let the missing area be x cm²

Therefore,

$\frac{x}{9} = \frac{8^2}{4^2}$

$\frac{x}{9} = \frac{64}{16}$

$\frac{x}{9} = 4$

Multiply both sides by 9

x = 9*4

x = 36 cm²

✔️Problem 2 (3-sided polygon):

Let the missing area be y cm²

Therefore,

$\frac{y}{240} = \frac{8^2}{32^2}$

$\frac{y}{240} = \frac{64}{1,024}$

$\frac{y}{240} = \frac{1}{16}$

Multiply both sides by 240

y = ¹/16 × 240

y = 15 cm²

✔️Problem 3 (5-sided polygon):

Let the missing area be z cm²

Therefore,

$\frac{z}{40} = \frac{3^2}{2^2}$

$\frac{z}{40} = \frac{9}{4}$

Multiply both sides by 40

$z = \frac{9}{4} * 40$

$z = \frac{9}{1} * 10$

z = 90 cm²

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Me asap!
(8x-2y)+(3x-4y)
a. 11x+8y
b. 4x-y
c. 11x-6y
d. 5x+2y