Me on my geometry question
the figure below shows a triangle with vertices a and b on a circle and vertex c outside it. side ac is tangent to the circle. side bc is a secant intersecting the circle at point x:
what is the measure of angle acb?
a. 32 degrees
b. 6 degrees
c. 24 degrees
d. 12

∠ABX is an inscribed angle.
The measure of an inscribed angle is half the measure of the intercepted arc ⇒
arc AX = 2*∠ABX = 2 * 64 = 128°

The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the intercepted arcs ⇒
∠ACB = (arc AB - arc AX)/2 = (152 - 128)/2 = 24/2 = 12°

I think 32 don't count me on it tho

First plot the y-intercept which is (0,-2)
Then using the slope plot another point, so up 4, to the right 7 and the point should be (2,7) and if you needed another point (6,14)
Then draw a line through it

I hope this helps