Mathematics: Me the body of a 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum. based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

Me the body of a 154-pound person contains approximately

Ответ:

only1yg

14.03.2022

Let a be aluminum and g be gold and k how many times:

2*10⁻¹mg a+ 6*10¹mg g= 154 lb

so a=kg

k=a/g

k=2*10⁻¹/6*10=1/300

a=1/300g

so Aluminum is 1/300 of gold.

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Ответ:

alexnunez07

30.03.2021

Mathematics

Absolute value #s will always be positive. If you know your transformation formula or what each variable does, then this will help you for your graph.

Step-by-step explanation:

4 is your shift from left to right We know this is a positive so it will be facing upwardsPlug in a # for x to check It would be C because it is +4 not -4 You can also use Desmos to plug in your equation or your graphing calculator

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Me the body of a 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum. based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

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