Mathematics: Mean of three numbers is 0 then what is mean of their cubes

Mean of three numbers is 0 then what is mean of

Johnson926

16.03.2022

$\frac{x^3+y^3+z^3}{3} =0$

Step-by-step explanation:

From the question we are told that

mean of three numbers is zero

Generally mean refers to average of number

Let

x, y, z be the three numbers with a mean of zero

T the mean of there cubes

Mathematically the mean of these three numbers is given as

$\frac{x+y+z}{3} =0$

x+y+z =0

and there cubes

$\frac{x^3+y^3+z^3}{3} =T$

x^3+y^3+z^3=3T

Mathematically solving the above equations by substitution method

x+y+z =0......1

x^3+y^3+z^3=3T ......2

x=-y-z ...3

equating 3 in 2

$-y^3-z^3+y^3+z^3=3T ..... 4\\3T=0$

T=0

Therefore the mean of the cubes of the three number is 0

$\frac{x^3+y^3+z^3}{3} =0$

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cbelew0001ouje4i

04.12.2021

The perpendicular line intersects with the parallel line.

Perpendicular lines have negative reciprocal slopes to parallel lines, so it intersects with the parallel line.

Parallel line: y = 5x + 3

Perpendicular line: y = -1/5x - 4

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