ljadalyn
13.05.2021 •
Mathematics
Mhanifa please help! I only have a few more...
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Ответ:
Step-by-step explanation:
a.
7x²-14=0
x²-2=0
(x+√2)(x-√2)=0
x=±√2
b.
disc.=6²-4(k+3)(k-5)=36-4(k²-5k+3k-15)
=-4(k²-2k-15)+36
=-4k²+8k+60+36
=-4k²+8k+96
=-4(k²-2k-24)
as it has 1 real solution.
so -4(k²-2k-24)=0
k²-2k-24=0
k²-6k+4k-24=0
k(k-6)+4(k-6)=0
(k-6)(k+4)=0
k=6,-4