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josiesolomonn1605
26.08.2020 •
Mathematics
Mila spends a winter day recording the temperature once every three hours for science class. At 9 am, the temperature was -1.6°F. Between 9am and noon, the temperature rose 6.6°F. Between noon and 3pm, the temperature increased by 2.8°F. Between 3pm and 6pm, the temperature went down 10.5°F. What was the temperature at 6pm?
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Ответ:
We can conclude the following information:
Every 3 hours the temperature changes.
At 9 AM, the temperature was -1.6°F:
9 AM = -1.6°F =>
Between 9 AM and noon, the temperature rose 6.6°F:
12 PM = -1.6 + 6.6 = 5°F =>
Between noon and 3 PM, the temperature increased by 2.8°F:
3 PM = 5 + 2.8 = 7.8°F =>
Between 3 PM and 6 PM, the temperature went down 10.5°F:
6 PM = 7.8 - 10.5 = -2.7°F
What was the temperature at 6 PM?
-2.7°F
Ответ:
The length of the shadow cast by the nearby building using the proportional relationship between the measure of the building and flagpole will be 125 feets
To obtain the length of the shadow cast by the building :
Length flagpole = lf = 40 feets
flagpole shadow = sf = 25 feets
Length building = lb = 200 feets
shadow of building = sb =?
(lf / sf) = (lb / sb)
(40 / 25) = (200 / sb)
Cross multiply :
40 × sb = 200 × 25
40 × sb = 5000
sb = 5000 / 40
sb = 125 feets
Therefore, the length of the shadow cast by the building will be 125 feets
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