Miss martinez purchase two kinds of candy for a math game. blow pops cost $.50 each and the sneakers cost $.60 each. she purchase a total of 30 pieces of candy for $16.80. writing system of equations that could be used to determine the each candy purchase if s represents the number of knickers and beat represents the number of blow pops purchased

We need to use the information given from the question to help us make our systems of equations

We know that Blow pops cost $0.50 each

We also know that Snickers cost $0.60 each

She bought 30 total pieces of candy

She spent a total of $16.80

First, lets make the systems of equation for the amount of candy she bought

We would represent blow pops as "b", and snickers as "s"

We know that she bought 30 pieces of candy, so our equation would = 30

We add b and s to get 30, so our equation would be:

b + s = 30

Systems of equation for the cost:

Represent blow pops as "b", and snickers as "s" for this equation too

We know that Blow pops cost $0.50 each and that Snickers cost $0.60 each

We know she spent a total of 16.80 dollars, so the equation would = 16.80

You would add 0.50b and 0.60s to get 16.80

The equation would be

0.50b + 0.60s = 16.80

b + s = 30

0.50b + 0.60s = 16.80

Line BL belongs to triangle BCL
Line CM belons to triangle BCM

The triangles BCL and BCM has a coomon side, the side BC, this side is congruent. 

If Angle XBA = Angle YCA, then:
Angle ABC or angle MBC of triangle BCM = Angle ACB or angle LCB of triangle BCL

If line BE is the bisector of angle ABC, then divides it into two equal parts, then angle MBL must be congruent with angle LBC

If line CD is the bisector of angle ACB, then divides it into two equal parts, then angle LCM must be congruent with angle MCB

As angle MBC is congruent with angle LCB, the angles MBL, LBC, LCM, and MCB must be congruents too.

Then angle MCB in triangle MBC is congruent with angle LBC of triangle BCL.

Then, the two triangles BCM and BCL have a congruent side (BC) and the two adjacent angles are congruent too (angle MBC of triangle BCM with angle  LCB of triangle BCL, and angle MCB of triangle BCM with angle LBC of triangle BCL).
Then by ASA the two triangles are congruents and the other two sides must be congruents too: Line BL of triangle BCL must be congruent with line CM of triangle BCM (because they are opposite to congruent angles: BL in triangle BCL is opposite to angle LCB, and CM in triangle BCM is opposite to angle MBC, and angles LCB and MBC are congruents).

I would use ASA to help me prove Line BL= Line CM