Modeling club A has 42 male models and 88 female model. Modeling club B has 20 male models fewer than Modeling club A. If the total number of models in both clubs is is 222, how many female models does Modeling club B have?

Given :

Modeling club A has 42 male models and 88 female model.

Modeling club B has 20 male models fewer than Modeling club A.

To Find :

If the total number of models in both clubs is 222, how many female models does Modeling club B have.

Solution :

Male model in club B is 20 less than male model in club A.

It is given that total number of models are 222.

Therefore, female models on club B are 70.

To solve the problem, you have to assume that each student shall receive the same number of cans of juice and the same number of packs of crackers.

Then, you need to find the greatest number that can divide both number of articles, 120 and 88. This is, you have to find the Greatest Common Factor (GCF) of 120 and 88.

To find the GCF you need to express each number as a producto of prime numbers. This is:

120 =2^3*3*5
88 = 2^3 * 11

Now, the GCF is the product of the common factors raised to the lower exponent. This is: 2^3 = 8.

Then you can invite 8 students, and each will receive 120/8 = 15 cans of juice and 88/8 = 11 packs of crackers.