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madeleine1102
31.05.2020 •
Mathematics
N
What is the solution set for this linear-quadratic system of equations?
y= x2 - x-12
y-x-3 = 0
A. {(-3,0), (0,3)}
B. {(-3,0), (4, 0);
C. {(-3,0), (5,8)}
D. {(4,0), (0,3)}
Solved
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Ответ:
C
Step-by-step explanation:
Given:![y=x^2-x-12\,,\,y-x-3=0](/tpl/images/0672/5639/b6e7d.png)
To find: solution set for this linear-quadratic system of equations
Solution:
A linear equation is an equation whose degree is 1 and degree of quadratic equation is 2.
Put
in ![y=x^2-x-12](/tpl/images/0672/5639/5655e.png)
For x = -3, y = -3+3=0
For x = 5, y = 5 + 3 = 8
So solutions are![\left ( -3,0 \right )\,,\,\left ( 5,8 \right )](/tpl/images/0672/5639/d13ff.png)
Option C. is correct
Ответ:
paki searech na lang po sa gogle
Step-by-step explanation:
parapo malaman nyu