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hiji0206
16.01.2021 •
Mathematics
NAME
7. Factor each quadratic expression,
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Ответ:
Step-by-step explanation:
x² - 2x - 35 = (x - 7)(x + 5).
x² + 3x - 54 = (x + 9)(x - 6).
x² - 4x + 4 = (x - 2)².
x² - 121 = (x + 11)(x - 11).
2x² + x - 15 = (2x - 5)(x + 3).
6x² - 7x - 24 = (3x - 8)(2x + 3).
3x² - 10x + 8 = (3x - 4)(x - 2).
10x² + 9x - 9 = (5x - 3)(2x + 3).
12x² + 25x + 12 = (4x + 3)(3x + 4).
15x² - x - 6 = (5x + 3)(3x - 2).
Ответ:
The steps described in the question are correct and correspond to a future value ordinary annuity formula, which can be seen in the image attached below.
The only thing I will changeis the value of the monthly interest rate.
I will use this formula, which gives a more accurate figure:
Where:
i = known interest ratea = number of compounding periods in a year for the known interest rateb = number of compound periods in a year for the unknown interst ratePlugging the amounts we obtain:
So our monthly interest rate is 0.351%
Now, we can solve the annuity equation
22,000 = X (1 - (1 + 0.043)^-6)) / 0.043
22,000 = X (5.927)
22,000 / 5.927 = X
3,711.8 = X
The monthly payments are therefore $3,711.8 each month.