Need a step by step on how to solve this

I have not done this in advance.  I'm just going to write it down
and see what I can do with it:

[ 1/(x+3)² - 1/x² ] / 3

Multiply the top and bottom by (x+3)² :

[ 1 - (x+3)²/x² ] / 3 (x+3)²

Multiply the top and bottom by x² :

[ x² - (x+3)² ] / 3 x² (x+3)²

Now it's just a matter of expanding and cleaning things up,
and hope and pray that a lot of things cancel.

Eliminate the parentheses on top and bottom:

[ x² - x² - 6x -9 ] / 3 x² (x² + 6x + 9)

Combine the x² terms on top, and divide top and bottom by 3 :

[ - 2x - 3 ] / x² (x² + 6x + 9)

Finally, all I can make of this is:

- (2x + 3) / [ x(x+3) ]² .

That's not a whole lot prettier than the original form, but at least
we got rid of those fractions in the numerator of a fraction.

I hope this is some help to you.

8x + 6y >/= 48 ......1

x + 2y >/= 12 .......2

The cost function is given as;

C = 0.05x + 0.03y .........3

The minimum cost is $0.24 at (0,8)

That is 0 ounces of oats and 8 ounces of rice.

Step-by-step explanation:

let x represent the number of ounces of oats

And y represent the number of ounces of rice

For Vitamin A

Minimum requirements = 48mg

x ounces of oats contribute 8mg × x

y ounces of Rice contribute 6mg × y

Therefore, we have;

8x + 6y >/= 48 ......1

For Vitamin B

Minimum requirements = 12mg

x ounces of oats contribute 1mg × x

y ounces of Rice contribute 2mg × y

Therefore, we have;

x + 2y >/= 12 .......2

The cost function is given as;

C = 0.05x + 0.03y .........3

Attached is the graphical representation.

The feasible points are (x,y) = (0,8),(2.4,4.8),(12,0)

The minimum cost is determined by substituting each point into the cost function

For (0,8)

C= 0.05(0) + 0.03(8)

C = $0.24

For (12,0)

C= 0.60

For (2.4,4.8)

C= $0.264

The minimum cost is $0.24 at (0,8)