wileycheyennem
11.10.2020 •
Mathematics
(NEED DONE QUICK) Triangle ABC has a midsegment at DF and segment DF is parallel to segment BC. What is the value of x?
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Ответ:
Step-by-step explanation:
Midsegment equals to half of the base
BC = 1/2 DF3x + 1 = 1/2*8(x - 6)3x + 1 = 4x - 244x - 3x = 1 + 24x = 25Ответ:
1C= x=9
1d= x=4
1e= x=4