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12.11.2020 •
Mathematics
NEED HELP ASAP! WILL MARK BRAINLIES! SERIOUS ANSWERS ONLY!
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Ответ:
Case 2 (n is odd): In this case n = 2k+1 for some integer k, and so, by substitution as above, n2 -
n + 3 = ... = 2(2k2 +2k + 1) + 1. Let t = 2k2 + 2k + 1. Then t is an integer because products and sums of
integers are integers. Hence, n2 - n + 3 = 2t + 1 where t is an integer, and so, by definition of odd, n2 -
n + 3 is odd.
in that case in both cases n2 - n + 3 is odd. yw
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