NEED THE ANSWER ASAP THANKS

its a

Step-by-step explanation:

Part a:   the x-intercepts are (3/2,,0).1. let y=0 to find the x-intercepts.0=2x^2-5x+32. split the second term in 2x^2-5x+30=2x^2-2x-3x+33. factor out common terms in the first two terms, then in the last two terms.0=2x(x-1)-3(x-1)4. factor out the common term x-10=(x-1)(2x-3)5. switch sides(x-1)(2x-3)=06. solve for xx=1,3/2 making it  (3/2,,0).part b:   not 100% sure but i think a minimum (5/4,-1/8)x=)/2*2x=5/4y=2(5/4)^2-5*5/4+3y=-1/8therefore, the parabola vertex is: (5/4,-1/8).part c: to graph it you'd use the vertex, focus, axis of symmetry, and the  directrix.vertex: (5/4,-1/8)focus: (5/4,0)axis of symmetry: x=5/4directrix: y=-1/4