Meliiiii
15.04.2020 •
Mathematics
Of the 15 novels written by a certain author, 8 were mysteries, 6 were romances, and 1 was a fantasy novel. The books were placed in groups of 6
How many groups of 6 books may be formed?
B) How Many groups of 6 will consist of all mystery books?
C) What is the probability that a group picked at random will consist of all mystery books?
D) What is the probably that a group, picked at random , will consist of 3 mysteries,
2 romances and 1 fantasy?
E) What is the probability the group of 6 will consist of all fantasy books?
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Ответ:
A) 3603600
B) 40320
C) 0.0112
D) 1.86 × 10^-15
E) 0
Step-by-step explanation:
Given the total number of books to be 15 novels
A) How many groups of 6 books may be formed?
This will be 15 permutation 6
15P6 = 15!/(15 - 6)!
= 3603600 groups
B) How Many groups of 6 will consist of all mystery books?
This will be 8 factorial
8! = 40320
C) What is the probability that a group picked at random will consist of all mystery books?
This will be
8! ÷ 15P6 = 40320 ÷ 3603600
= 0.0112
D) What is the probably that a group, picked at random , will consist of 3 mysteries, 2 romances and 1 fantasy? This means
8C3/15P6 × 6C2/15P6 × 1C1/15P6
0.00016 × 0.000042 × 0.00000028
1.86×10^-15
E) What is the probability the group of 6 will consist of all fantasy books?
The probability is approximately equal to zero.
E) What is the probability the group of 6 will consist of all fantasy books?
Ответ:
A po
Step-by-step explanation:
sana makatulong haaha