Mathematics: On a coordinate plane, trapezoid j k l m is shown. point j is at (negative 7, 4), point k is at (negative 4, 4), point l is at (negative 2, 3), and point m is at (negative 8, 3). what is the perimeter of trapezoid jklm? startroot 2 endroot + startroot 5 endroot units 2 + startroot 2 endroot + startroot 5 endroot units 9 + 2 startroot 2 endroot units 9 + startroot 2 endroot + startroot 5 endroot units

The answer is B because it goes up 1 and over 3...

On a coordinate plane, trapezoid j k l m is shown.

maria051002camp

15.01.2022

the perimeter = $9+\sqrt{2} +\sqrt{5} \ units$

Step-by-step explanation:

see the attached figure.

the perimeter of trapezoid JKLM = JK + KL + LM + MJ

The distance between two points (x₁ , y₁) and (x₂ , y₂)

= $\sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2 }$

Given the points L=(-7,4) , K=(-4,4) , L=(-2,3) and M=(-8,3)

JK = $\sqrt{(-7-(-4))^2+(4-4)^2 }= 3$

KL = $\sqrt{(-4-(-2))^2+(4-3)^2 }= \sqrt{5}$

LM = $\sqrt{(-2-(-8))^2+(3-3)^2 }= 6$

MJ = $\sqrt{(-8-(-7))^2+(3-4)^2 }= \sqrt{2}$

So, JK + KL + LM + MJ = $3+\sqrt{5} + 6 + \sqrt{2}$

So, the perimeter = $9+\sqrt{2} +\sqrt{5} \ units$

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