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finnierunners2
18.10.2019 •
Mathematics
On the first part of a trip to carmel traveling on the freeway, marge averaged 70 mph. on the rest of the trip, which was 25 mi longer than the first part, she averaged 60 mph. find the total distance to carmel if the second part of the trip took 30 minutes more than the first part.
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Ответ:
95 miles
Step-by-step explanation:
Let the distance traveled in first part be x
Speed = 70 mph
So, Time =![\frac{Distance}{Speed} =\frac{x}{70}](/tpl/images/0332/4220/7c0a4.png)
We are given that On the rest of the trip, which was 25 mi longer than the first part, she averaged 60 mph.
So, distance in second part = x+25
Speed = 60
So, Time =![\frac{Distance}{Speed} =\frac{x+25}{60}](/tpl/images/0332/4220/2e49c.png)
Now we are given that he second part of the trip took 30 minutes more than the first part.
So, total distance = distance in first part+ distance in second part = x+x+25=35+35+25= 95
Hence the total distance is 95 miles
Ответ:
subtract 7 from both sides or substitute five i suppose
p + 7 = 12
p+7-7 = 12-7
p = 5