(on the line y=2×+3. find the other half of the

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yungkxng57

03.06.2020

$\dfrac{\sin a+2\cos a}{\sin^2 a+2\sin a \cos a} = \csc a$ working on the left-hand side as that's more complicated: $\text{lhs} = \dfrac{\sin a+2\cos a}{\sin^2 a+2\sin a \cos a}$ in the denominator, factor out sin a $\text{lhs} = \dfrac{\sin a+2\cos a}{\sin a\left( \sin a+2 \cos a\right)}$ we have a (sin a + 2 cos a) in both the numerator and denominator. they cancel each other out. $\begin{aligned} \text{lhs} & = \dfrac{\boxed{\sin a+2\cos a}}{\sin a\boxed{\left( \sin a+2 \cos a\right) } } \\ & = \frac{1}{\sin a} \end{aligned}$ by definition, csc a = 1/sin a so $\begin{aligned} \text{lhs} & = \csc a \\ & = \text{rhs} \end{aligned}$

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(on the line y=2×+3. find the other half of the coordinate

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