On the plane curve defined by the parametric equations below, what point corresponds to t= -1 x=2t-1 y=t^3 (2,1) (1,2) (-1,3) (-3,-1)

The equation x=2t-1 represent the x-coordinate. To get the value of x, substitute t with -1.

That is:  x = 2(-1) - 1
                 = -2-1 
                = -3
Likewise, the equation y=t∧-3 represent the y-coordinate. Substituting t with -1,
 
  y = (-1)∧-3
    = -1

The point that correspond to t=-1 is (-3,-1).

H

Step-by-step explanation:

Y= (x+2)^2-5

2 to the left x+2=0 x=-2

5 dpwn