One angle of two supplementary angles is four times the other angles is four times the other angle. find the mesures of the two angles

Supplementary angles add up to 180 degrees

a + b = 180
a = 4b

4b + b = 180
5b = 180
b = 180/5
b = 36 <=== here is 1 angle

a = 4b
a = 4(36)
a = 144 <== and here is the other one

(1/(25^3×2))^(1/3)25^3 = 25×25^2: (1/(25×25^2×2))^(1/3)  | 2 | 5× | 2 | 51 | 2 | 55 | 0 | 06 | 2 | 5: (1/(25×625×2))^(1/3)25×625 = 15625: (1/(15625×2))^(1/3)15625×2 = 31250: (1/31250)^(1/3)(1/31250)^(1/3) = (1^(1/3))/(31250^(1/3)): (1^(1/3))/(31250^(1/3))31250^(1/3) = (2×5^6)^(1/3) = 5^2 2^(1/3): (1^(1/3))/(5^2 2^(1/3))5^2 = 25: (1^(1/3))/(25 2^(1/3))rationalize the denominator. (1^(1/3))/(25 2^(1/3)) = (1^(1/3))/(25 2^(1/3))×(2^(2/3))/(2^(2/3)) = (1^(1/3)×2^(2/3))/(25×2): (1^(1/3)×2^(2/3))/(25×2)25×2 = 50: answer: (1^(1/3)×2^(2/3))/(50)