One factor of one factor of f(x)=5x^3+5x^2-170x + 280 is (x +
7). what are all the roots of the function? use the remainder theorem.
x = –4, x = –2, or x = 7
x = –7, x = 2, or x = 4
x = –7, x = 5, or x = 280
x = –280, x = –5, or x = 7

Option 2 is correct

Step-by-step explanation:

We have been given an expression

Since, we have given a factor (x+7) that means at x=-7 the value of given expression will be zero

Similarly we have to check the given points where  they are giving values 0.

Let us check at x=-4 that means put x=-4 in given expression we will get

We are getting

Hence, x=-4 is dicarded

Hence, option 1 is discarded.

Now, we will check at x=2 we will get

Hence, x=2 is factor of given function.

Now, we will check at x=4

Hence, x=4 is also a factor of given function.

Option 2 is correct