Mathematics: One root of f(x)=x^3+10x^2-25-250 is x = –10. what are all the roots of the function? use the remainder theorem. x = –25 or x = 10 x = –25, x = 1, or x = 10 x = –10 or x = 5 x = –10, x = –5, or x = 5

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One root of f(x)=x^3+10x^2-25-250 is x = –10. what - id31022525010191065, skyvargasov9cad

josephmartinelli5

28.05.2020

All zeros are

x=-10 , x=-5 , x=5

Step-by-step explanation:

we are given function as

f(x)=x^3+10x^2-25x-250

we are given one of zero is x=-10

we have to use Remainder theorem

we can find all possible factor of 250

$250=-5\times 5\times -10$

so, we will check zeros at x=-5 and x=5

At x=-5:

we can plug x=-5

f(-5)=(-5)^3+10(-5)^2-25(-5)-250

$f(-5)=-125+250-\left(-125\right)-250$

f(-5)=0

At x=5:

we can plug x=5

f(5)=(5)^3+10(5)^2-25(5)-250

$f(5)=125+250-\left(125\right)-250$

f(5)=0

So, other zeros are

x=-5 and x=5

All zeros are

x=-10 , x=-5 , x=5

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