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rainbowcakes914
14.01.2020 •
Mathematics
Oneta writes an algebraic a spression with 3 terms. the y-term has a coefficient of negative 3 and the x-term has a coefficient of one. the expression does not have a constant term which expression could she have written.
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Ответ:
Option a. x - y^2 - 3y
Step-by-step explanation:
The options of the questions are
a. x - y^2 - 3y
b. x - 3y + 6
c. x + 3y^2 + 3y
d. x + 3y + 7
we know that
The expression has 3 terms
The y-term has a coefficient of negative 3 and the x-term has a coefficient of one
The expression does not have a constant term
Verify each case
case a) we have x - y^2 - 3y
The expression has 3 terms > is ok
The y-term has a coefficient of negative 3 ---> is ok
The x-term has a coefficient of one > is ok
The expression does not have a constant term > is ok
therefore
She could have written this expression
case b) we have x - 3y + 6
The expression has 3 terms > is ok
The y-term has a coefficient of negative 3 ---> is ok
The x-term has a coefficient of one > is ok
The expression does not have a constant term ---> is not ok (the expression have a constant term of 6)
therefore
She couldn't have written this expression
case c) we have x + 3y^2 + 3y
The expression has 3 terms > is ok
The y-term has a coefficient of negative 3 ---> is not ok (the y-term has a coefficient of positive 3)
therefore
She couldn't have written this expression
case d) we have x + 3y + 7
The expression has 3 terms > is ok
The y-term has a coefficient of negative 3 ---> is not ok (the y-term has a coefficient of positive 3)
therefore
She couldn't have written this expression
Ответ:
It is 4
Step-by-step explanation: