TheRunningPotatoe245
23.06.2020 •
Mathematics
Organisms A and B start out with the same population size.
Organism A's population doubles every day. After 6 days, the
population stops growing and a virus cuts it in half every day for 4
days.
Organism B's population grows at the same rate but is not infected
with the virus. After 10 days, how much larger is organism B's
population than organism A's population?
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Ответ:
At the end of ten days, the size of population B is 256 times that of population A
Step-by-step explanation:
We work under the premise that population A and B start both with the same number of individuals. Let's call such initial population
Now, we write the exponential expression that describes population A as a function of days (t) for the first 6 days:
which represents the starting point with individuals on day zero, doubling after one day (t= 1), and keeping on doubling the following days for 6 days.
So at the end of 6 days, population A would have the following number of individuals:
That is 64 times the starting number of individuals.
After this, the population stops growing and starts reducing to one-half each day. This behavior can be represented by:
therefore after 4 days in this pattern, this culture has the following number of organisms:
which is now just four times what the culture started with.
Now, on the other hand, population B grows doubling each day without interruption, so at the end of 10 days its size is given by:
that is it has 1024 times the initial number of organisms.
So if we compare both populations at day 10:
Therefore, at the end of ten days, population B is 256 times the size of population A
Ответ:
c
Step-by-step explanation: