gdominguez2005
18.03.2020 •
Mathematics
Out of 3000 light bulbs that were tested, 126 were defective. find the prbability of defective and non defective
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Ответ:
P(defective) = 126/3000 = 0.042
P(not defective) = 1 - P(defective)
= 1 - 0.042 = 0.958
Ответ:
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