Mathematics: Part 1 of 2 a square plate is produced by welding to- gether four smaller square plates, each of side a. the weight of each of the four plates is shown in the figure. (2a, 2a) (0,2a) 10 n 30 n 60 n 70 n (0,0) (2a, 0) find the x-coordinate of the center of gray- ity (as a multiple of a). answer in units of a. 0909 part 2 of 2 find the y-coordinate of the ity (as a multiple of a). answer in units of a.

So what you need to do is add the measurements of P and Q AND A,B which would be 185...

Part 1 of 2 a square plate is produced by welding

Ответ:

chasitythompso1

15.01.2022

Mathematics

( $\frac{37a}{34}$ , $\frac{25a}{34}$ )

Step-by-step explanation:

Given data,

Side of square = a

center of gravity of x,y

$x_{cg}$ = $\frac{w_{1}x_{1} +w_{2}x_{2}+......+w_{n}x_{n} }{w_{1}+w_{2}+......+w_{n} }$

$y_{cg}$ = $\frac{w_{1}y_{1} +w_{2}y_{2}+......+w_{n}y_{n} }{w_{1}+w_{2}+......+w_{n} }$

now, find the center of mass of each plate

For plate 1

W = 10N

x- coordinate = a/2

y- coordinate = a+a/2 = 3a/2

For plate 2

W = 30N

x- coordinate = a+a/2=3a/2

y- coordinate = a+a/2 = 3a/2

For plate 3

W = 70N

x- coordinate = a+a/2=3a/2

y- coordinate = a/2

For plate 4

W = 60N

x- coordinate = a/2

y- coordinate = a/2

$x_{cg}$ = $\frac{10\times\frac{a}{2} +30\times\frac{3a}{2}+70\times\frac{3a}{2}+60\times\frac{a}{2}}{10+30+70+60 }$ = $\frac{185a}{170}$ = $\frac{37a}{34}$

$y_{cg}$ = $\frac{10\times\frac{3a}{2} +30\times\frac{3a}{2}+70\times\frac{a}{2}+60\times\frac{a}{2}}{10+30+70+60 }$ = $\frac{125a}{170}$ = $\frac{25a}{34}$

Therefor ( $\frac{37a}{34}$ , $\frac{25a}{34}$ ) will the center of gravity

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