⦁part a-find the perimeter of the outside edges of the frame. explain and show your work! perimeter outside: 24 part b-find the area of the inside of the frame where the picture would belong and the area of the entire frame using the outside values. explain and show your work! area inside: 24 area outside: 35

Answer of part A:

Outside Width of the frame = 5 in

Outside Length of the frame = 7 in

Since frame is rectangular so we can use formula of perimeter of rectangle which is:

Perimeter = 2(Length + width) = 2(5+7)= 2(12)= 24 in

There is scale factor of 1 in = 2.5 ft

So perimeter in ft will be = 24*2.5 = 60 ft.

Answer of part B:

Inside Width of the frame = 4 in

Inside Length of the frame = 6 in

Since frame is rectangular so we can use formula of area of rectangle which is:

Area = Length * width = 4*6 = 24 square in.

Hence area of the inside of the frame where picture would belong = 24 square inches.

Question doesn't say to find your answer in feet as given in scale factor so i'm skipping the conversion. You can convert that into ft if needed using the process, explained in part A.

Outside Width of the frame = 5 in

Outside Length of the frame = 7 in

Area made by outer side of the frame = 5*7= 35 square in.

Now the actual area of the frame will be area between Outer Frame and Inner frame which is just difference of both areas

so we get 35-24= 11 square in.

Hence area of the entire frame except the picture area = 11 square in.

its actually a=-5 b=1 c=-5 d=-12 i just did this and these were the correct answers.