Passing through the points (-2,3) and (-2,6). find an equation for the line described

The slope -intercept form of linear equation is y=mx+b.

Where m= slope and b=y-intercept.

Formula to find m is,

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

The line passes through (-2,3) and (-2,6).. So, we can plug in x1=-2, y1=3, x2=-2 and y2=6 in the above formula. So,

m=\frac{6-3}{(-2)-(-2)}

m=\frac{3}{-2+2}

m=\frac{3}{0}

Since 0 is at the denominator so, m= undefined because there is no change in x. Whatever be the values of y but x will also be -2.

So, the equation will be x=-2.

"Use Pythagorean Theorem to solve (a right triangle with the base being one of the side lengths and the height being the other side length.  a^2 + b^2 = c^2
64^2 + 100^2 = length of diagonal ^2
4096 + 10000 = 14096
The length of the diagonal is the square root of 14096 or 118.727 meters (rounded to the thousandths place). "
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