bluepanda21
19.08.2019 •
Mathematics
Pat bought a boat for $37,000 in 2001. in 2006 the boat was worth $27,000. if the boat depreciation is linear, how much will the boat be worth in 2009?
a) $27,000
b) $22,000
c) $21,000
d) $20,000
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Ответ:
C) $21,000
Step-by-step explanation:
Given : Pat bought a boat for $37,000 in 2001. In 2006 the boat was worth $27,000.
If the boat depreciation is linear, then the amount by which the value of boat depreciates must be constant.
Let x be the constant depreciation in the value of boat per year.
Then , the value of boat (in dollars) after n years from 2001 is given by :-
(1)
For year 2006 , n=5 and V = 27000
Then ,
i.e.
i.e.
i.e.
Thus , the constant amount of depreciation in the value of boat per year. = $2000
Now for year 2009 , put in n=8 and x= 2000 in (1), we get
Hence, the value of boat in 2009 = $21,000
Ответ: